6. Two boxes A and B of weight 250 N and 150 N respectively are placed on an inclined
surface as shown in figure 6. Determine value of a so that motion of boxes impends down the
plane. Assume coefficient of static friction between block A and inclined surface as 0.30 and
between block B and inclined surface as 0.20
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A = Tan^-1 (0.3)
downward F along incline 《 frictional Resistance Force caused by Static Friction
mg sin theta 《 Mustatic x mg Cos Theta ( mg cos Theta is Normal Formal force from incline )
Tan A 《 Mu = 0.3
A = Tan^-1 0.3
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