6. What is the value of the discriminant of the quadratic equation x²+ 22x + 121 = 0? *
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Answer:
x=−11 (multiplicity 2). Explanation: this is a perfect square. ∙x(a±b)2 =a2±2ab+b2. with a=x and b=11. 2ab=2×x×11 =22x.
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