6. When x = 1, y = 2 and z = -3, find the value of x2 + y2 + z2-3xy2-xy
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Answered by
1
Answer:
0
Step-by-step explanation:
x = 1 and y = 2 and z = -3
Thus, substituting the values,
(1)²+ (2)² + (-3)² - 3(1)(2)²-(1)(2)
= 1 + 4 + 9 - 3(4) -2
= 5 + 9 - 12 - 2
= 14 - 14
=0
Answered by
0
Answer:
24
Step-by-step explanation:
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