Question

6. Which digit would occupy the units place of 6 power 100​

Answer 1

6 raised to any power has the last digit as 6 only.6

6 × 6 = 36

6 × 6 × 6 = 216

6 × 6 × 6 × 6 = 1296

So, the last digit of 6^100 is 6.

Answer 2

Given: Here we have the digit 6

To find: digit would occupy the units place of 6 power 100​

Solution:

Here we have

$6^1=6\\6^2=36\\6^3=1296$

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$6^n$ has always 6 in its unit place

Therefore, $6^{100}$ has 6 in its unit place

Final answer:

Hence the answer is 6.