6(x – 5)4 + 4(x – 5)2 + 6 = 0
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Answered by
1
Answer:
how to solve rational number 1 7
5 8
Answered by
0
Answer:
6u²+4u+6=0
Step-by-step explanation:
We have ,
6(x-5)²+² +4(x-5)²+6=0
Let,
u =(x-5)²
remember that,
if , u =(x-5)²
then,
u² = (x-5)²+²
substitude
6u² + 4u +6 =0 ___________________> Quadratic equation.
(Note - where i have put power 2+2 there you can write 4 .)
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