Question

(6+x) (x^2 +4x-1) = 0​

Answer 1

$(6+x) (x^2 +4x-1) = 0$

$=>6(x²+4x-1)+x(x²+4x-1)=0$

$=>6x²+24x-6+x³+4x²-1=0$

$=>x³+6x²+4x²+24x-6-1=0$

$=>x³+10x²+24x-7=0$

$This$$equation$$is$$not$$true.$