Question

6 - x - x²


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Answer 1

Answer

- ( x - 3 ) ( x - 2 )

Given

6 - x - x²

To Find

To solve the given equation

Solution

$\rm 6-x-x^2\\\\\to \rm -(x^2+x-6)$

Now , factorize the given equation using middle term splitting method ,

$\to \rm -(x^2+3x-2x-6)\\\\\to \rm -\{ x(x-3)-2(x-3)\}\\\\\to \rm -\{(x-3)(x-2)\}\\\\\to \rm -(x-3)(x-2)\ \; \red{\bigstar}$

Answer 2

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- ( x - 3 ) ( x - 2 )

Given

6 - x - x²

To Find

To solve the given equation

Solution

\begin{gathered}\rm 6-x-x^2\\\\\to \rm -(x^2+x-6)\end{gathered}

6−x−x

2

→−(x

2

+x−6)

Now , factorize the given equation using middle term splitting method ,

\begin{gathered}\to \rm -(x^2+3x-2x-6)\\\\\to \rm -\{ x(x-3)-2(x-3)\}\\\\\to \rm -\{(x-3)(x-2)\}\\\\\to \rm -(x-3)(x-2)\ \; \red{\bigstar}\end{gathered}

→−(x

2

+3x−2x−6)

→−{x(x−3)−2(x−3)}

→−{(x−3)(x−2)}

→−(x−3)(x−2) ★

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