Question

What will be the deformation of spring if a block of weight 100n is kept in it. Take stiffness of string 1000n/m?

Answer 1

Explanation:

deformation = force / stiffness

= 100 / 1000 = 0.1 m

Answer 2

The deformation of spring is 0.1 m.

Explanation:

Given the weight of the block F = 100 N.

The spring consatnt (stiffness of string), k = 1000 N/m.

To calculate the deformation of the spring, use Hooke's law as

F = kx

Here, x is the Spring deflection.

substitute the given values, we get

$100N=x\times1000N/m$

 $x=\frac{100N}{1000N/m}$

x = 0.1 m.

Thus, the deformation of spring is 0.1 m.

#Learn More: Hooke's law.

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