6 years ago B mothers age (that time) was 3 times her age (that time .8 years hence the respective ratio of their ages (that time)will be 17:8.what is the respective ratio of B present age and her mother present age
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Answer: Present age of mother = 39, Present age of son = 17
Working: 6 years ago say son’s age was X. so, mother’s age was 3X
Present age of mother = 3X +6, Present age of son = X+6
After 5 years mother’s age = 3X+11, Son’s age = X+11
Given > 3X+11 = 2(X+11) = 2X+22
or, 3X-2X = 22–11
or, X = 11
Hence, present age of mother = 3X+6 = 39 and present age of son = X+6 = 17.
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