Question

6
years back the age of Muneer was
3 times the age of Mujeeb. After 4 years
of Muneer becomes twice the
age of Mujeeb. Find the
age
of two
of them now.​

Answer 1

Answer:

18 years.

Step-by-step explanation:

6 years back the age of Muneer was 3 times the age of Mujeeb. After 4 years the age of Muneer becomes twice the age of Mujeeb.

Find the age of two of them now.

Age of Muneer 6 years back = 3(4 + 6) = 18 years.

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Answer 2

Answer:

muneer is 36yrs old and mujeeb is 16 yrs old

Step-by-step explanation:

Let the present age of muneer be 'x'

let the present age of mujeeb be 'y'

6 years ago

muneer's age =x-6

mujeeb's age=y-6

so the equation

x-6=3(y-6)

x-6=3y-18

x-3y= -12 ---------(1)

4 years hence

muneer's age=x+4

mujeeb's age=y+4

so the equation

x+4=2(y+4)

x+4=2y+8

x-2y=4 --------(2)

from 1 and 2

x-3y= -12

(--) x-2y=4

(-) (+) (-)

------------------------

-y=-16

y=16

so,

x-2y=4

x-2(16)=4

x-32=4

x=36

present age of muneer is 36yrs

present age of mujeeb is 16yrs