Question

6 years hence, a man's age will be three times the age of his son and three years ago, he was nine times as old as his son. The present age of the man is

Answer 1

Answer:

let mans age= x

let his son age= y

6 years hence: mans age= x+6

                         sons age= y+6

3 years ago: mans age= x-3

                     sons age= y-3

according to the question:-

(x+6)=3(y+6)

x+6=3y+18

x-3y=12----------(i)

(x-3)=9(y-3)

x-3=9y-27

x-9y= -24-----------(ii)

subtracting equations (i) - (ii):

6y= 36

y=36/6

y=6  [substitute this value in equation (i)]

we get, x-3(6)=12

x-18=12

x=12+18

x=30

hence age of father is 30 years & age of his son is 6 years at present

hope it helps you!!...

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