60 gram of compound on analysis gave 24 grams carbon ,4 grams hydrogen , 32 grams of oxygen .EMPIRICAL formula of the compound is
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Assuming that the third element is oxygen
carbon=24/12=2
hydrogen=4/1=4
oxygen=32/16=2
so the empirical formula is c2h4o2
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Assuming that the third element is oxygen
carbon=24/12=2
hydrogen=4/1=4
oxygen=32/16=2
so the empirical formula is c2h4o2
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