60. In the given figure, PR is bisector of <QPS and
triangle SOR is an isosceles triangle with equal sides SO
and SR, then OS-OQ equals
(1)OQ/OR
(2)OP/OQ x OR
(3) OQ x OR / OP
(4) OP/OR
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According to given figure.
PQ=PR(giventhat)
QS=SR(Bydefinationofmidpoint)
PS=PS(Commonline)
Then,
ΔSPQ≅ΔSPR (BY congruency S.S.S.)
Hence, PS bisects ∠PQR by definition of angle bisector.
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