Question

60 joules work is done, when a force ‘F’ causes a displacement of 10 m. The magnitude of force is:
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Answer 1

Answer:

$\boxed{\mathfrak{Force \ (F) = 6 \ N}}$

Given:

Work done (W) = 60 J

Displacement (d) = 10 m

To Find:

Force (F)

Explanation:

Work done by the force is defined as the product of component of the force in the direction of the displacement and the magnitude of the displacement.

$\boxed{ \bold{W = Fd \: cos \theta }}$

As in the given question force is acting along the displacement.

So,

$\sf \theta = 0^{\circ}$

Now, by substituting values of W, d & $\sf \theta$ in the formula we get:

$\sf \implies 60 = F \times 10 \times cos \: 0 ^{ \circ} \\ \\ \sf \implies 60 = F \times 10 \times 1 \\ \\ \sf \implies 10F = 60 \\ \\ \sf \implies F = \frac{60}{10} \\ \\ \sf \implies F = 6 \: N$

$\therefore$

Magnitude of force = 6 N

Answer 2

Answer:

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Explanation:

work done =60 joules

displacement = 10 m

we must to substitute and value we will get

and the answer is

magnitude =6n