Question

60 men do a piece of work in 27 days, then in how many days 18 men do the same work​

Answer 1

Answer:

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Step-by-step explanation:

Another approach is by the unitary method, which is simpler to understand.

Let the amount of work being done by 30 men in 27 days be x.

Then the amount of work done by 30 men in 1 day is x/27.

The amount of work done by 1 man in 1 day will be (x/27) /30 = x/(27*30)

The amount of work done by 18 men in 1 day will be, (x/(27*30)) *18

So now we know how much work 18 men can do in a single day.

The amount of work to be done by these 18 men is thrice of the previous work, I.e. It is 3x.

Thus, the no. Of days required = total amount of work/work done per day

=3x/(x*18/27*30)=135 days

Here you basically Try to find how much work is done by one person in one day, and using that you find how much work 18 men will do in one day, which leads you to the final answer.

Answer 2

Answer:

90 Days

Step-by-step explanation:

Total man-days for doing the work is 60*27 = 1620

Days 18 men will take to do the same work = 1620/18 = 90 Days

The Answer is 90 Days.

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