Question

60% of diatomic gas is dissociated to monoatomicgas. What is Cp/Cv for this situation ​

Answer 1

Explanation:

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Answer 2

Cp/Cv = 9/19

Given:

60% diatomic gas dissociates to monoatomic gas.

To find:

Cp/Cv for this situation ​

Solution:

The mixture contains 60% monoatomic gas and 40% diatomic gas.

Cv of monoatomic gas: 3/2R

Cv of diatomic gas: 5/2R

Cv of the given mixture is given by: [ n₁ (Cv)₁ + n₂ (Cv)₂ ] / [n₁ + n₂]

Cv of the mixture: [3/5 × 3/2R + 2/5 × 5/2R]

Cv of the mixture: 19/10R

Since Cp = Cv - R

Cp of the mixture = 19/10R - R

Cp of the mixture = 9/10R

γ = Cp/Cv

γ = 9/19

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