Question

60 points..☺☺

➡️differentiate this..
find dy/dx

#class 12th​

Answer 1

Answer:

Refer the attached picture.

Answer 2

Answer:

Step-by-step explanation:

find dy/dt and dx/dt

dy/dt=d/dt(cos^3 t/ cos 2t^1/2 )

use u/v rule

------>(u.dv/dt+v.du/dt)/v^2

differentiation of cos 2t^1/2= -sin2 t/cos 2 t^1/2

differentiation of cos^3 t is -3 cos^2 t sin t

dy/dt=[(cos^3 t*(-sin 2t/cos 2 t^1/2))+(( cos 2 t^1/2)*(-3 cos^2 t sin t))]/cos 2t

dx/dt=[(sin^3 t*(-sin 2t/cos 2 t^1/2))+(( cos 2 t^1/2)*(3 sin^2 t cos t))]/cos 2t

ans is cot t