600 insects :200 are homozygous purple, 150 are heterozygous purple, 250 are homozygous green. calculate p (square ) &q. From Hardy Weinberg equilibrium no theoretical answer. Take help from Google or form any elder. hai koi maikalal ya maikalali jo is ka answer de skta hai
Answers
Answer:
1. The frequency of two alleles in a gene pool is 0.19 (A) and 0.81(a). Assume that the population is in
Hardy-Weinberg equilibrium.
(a) Calculate the percentage of heterozygous individuals in the population.
According to the Hardy-Weinberg Equilibrium equation, heterozygotes are represented by the 2pq
term. Therefore, the number of heterozygous individuals (Aa) is equal to 2pq which equals
2 × 0.19 × 0.81 = 0.31 or 31%
(b) Calculate the percentage of homozygous recessives in the population.
The homozygous recessive individuals (aa) are represented by the q
2
term in the H-W equilibrium
equation which equals 0.81 × 0.81 = 0.66 or 66%
2. An allele W, for white wool, is dominant over allele w, for black wool. In a sample of 900 sheep, 891 are
white and 9 are black. Calculate the allelic frequencies within this population, assuming that the
population is in H-W equilibrium.
The allelic frequency of w is represented by the q term and the allelic frequency W is represented by the
p term. To calculate the value of q, realize that qq or q
2
represents the homozygous recessive individuals
or the black sheep in this case. Since there are 9 black sheep, the frequency of black sheep
=
# individuals 9 0.01
total individuals 900 = = , thus ww = q
2 = 0.01
∴ 2
q q == = 0.01 0.1
Additionally, p + q = 1 thus p = 1 – q or p = 1 – 0.1 or 0.9 ∴ p = W = 0.9 and q = w = 0.1
3. In a population that is in Hardy-Weinberg equilibrium, the frequency of the recessive homozygote
genotype of a certain trait is 0.09. Calculate the percentage of individuals homozygous for the dominant
allele.
We know that the frequency of the recessive homozygote genotype is q
2 and equal to 0.09.
∴ 2
q q == = 0.09 0.30 AND we also know that p + q = 1
Thus, p = 1 – q ∴ p = 1 – 0.30 = 0.70
∴The homozygote dominants are represented by p
2 = (0.70)2
= 0.49 or 49%