Question

6000 for 2 years at 9% per annum compounded annually.
By using formula.

Answer 1

Heya friend,

Given that

P = ₹6,000

R = 9 % p.a.

T = 2 years

Solution

When the interest is compounded annually.

C.I. = P{(1 + R/100)^n - 1}

= 6,000 {(1 + 9/100)^2 - 1}

= 6,000 {(100 + 9/100)^2 - 1}

= 6,000 {(109/100)^2 - 1}

= 6,000 {11,881/10,000 - 1}

= 6,000 {11,881 - 10,000/10,000}

= 6,000 × 1,881/10,000

= ₹ 1,128.60







Thanks

With regards@

Tanisha

Answer 2

Answer:

$:\implies\sf Amount = P \bigg\lgroup 1 + \dfrac{R}{100}\bigg\rgroup^{n}$

$:\implies\sf Amount = 6000 + \bigg\lgroup 1 + \dfrac{9}{100}\bigg\rgroup^2$

$:\implies\sf Amount = 6000 \big\lgroup 1 + 0.09\big\rgroup^2$

$:\implies\sf Amount = 6000 \big\lgroup 1.09\big\rgroup^2$

$:\implies\sf Amount = 6000 \big\lgroup 1.1881\big\rgroup$

$:\implies \underline{ \boxed{\sf Amount =Rs. \: 7128.60 }}$

$\therefore\:\underline{\textsf{The Amount is \textbf{Rs. 7128.60}}}.$

________________________

⠀

$\dashrightarrow\:\:\sf Compound \: Interest = Amount - Principal$

$\dashrightarrow\:\:\sf Compound \: Interest = 71286.60 - 6000$

$\dashrightarrow\:\:\underline{\boxed{\sf Compound \: Interest = 1128.6}}$

$\therefore\:\underline{\textsf{The Compound Interest is \textbf{Rs. 112.86}}}.$