Question

60°C is mixed2 kg of water at with 1 kg of water at 30°C kept in a vessel of heat capacity 200 J/K. Spe
of water is 4,200 J/kg/K. Then final temperature is nearly
(a) 50°C
(b) 35°C
(c) 45°C
(d) 55°C​

Answer 1

Answer:

You need to understand 3 concepts to solve this answer.

Firstly, You have to use the principle of calorimetry (measuring heat content of a system) to get the answer for this question.

The principle goes like this:

heat gained by a system(ice) = heat given by a system (water).

That means the heat absorbed by ice will be equal to the heat given by the water.

Secondly,now since you know the principle, next step is to know the formula of heat given or taken, that is

Q= m*c*(t2-t1)

where,

m=mass of the substance

c=heat capacity of substance (ice=2.1kJ/kgK, water=4.2kJ/kgK)

t2-t1=change in temperature of the substance

So your final formula would be:

Heat given by water = heat absorbed by ice + latent heat + heat absorbed by water (melted ice)

Answer 2

Answer:

your answer is in attachment