Question

600ml of a gas contains o2 and o3 which has a mass of 1g.Calculate the volume of O3 in it.

Answer 1

Let the volume of ozone be V ml.
Volume of oxegen = (600-V) ml
Mass of 22,400 ml of ozone at STP = 48 g (Molar mass of O3 is 48 )
Mass of V ml of ozone = 48 x V/22400 g
Mass of 22,400 ml of oxygen = 32 g (Molar mass of O2 is 32)
Mass of (600-V) ml of oxygen = 32 x (600-V)/22400 g
Now, 48 x V/22400 + 32 x (600-V)/22400 = 1
48 x V + 32 x (600-v) = 22400
48 V- 32 V = 22400 - (32 x 600)
16 V = 3200
V = 200 ml. (answer)