Math, asked by dipshikhachatte3993, 18 days ago

60a⁶÷(4a³+a³)- ⅗ of (6a³+18a⁴÷2a)

Answers

Answered by nilesh102
3

Solution :

⟹ 60a⁶/(4a³ + a³) - 3/5 * (6a³ + 18a⁴/2a)

= 60a⁶/5a³ - 3/5 * (6a³ + 9a³)

= 60a⁶/5a³ - 3/5 * (6a³ + 9a³)

= 12a³ - 3/5 * 15a³

= 12a³ - 3 * 3a³

= 12a³ - 9a³

= 3a³

More info : Use BODMAS RULE to solve the problem.

BODMAS RULE :

The BODMAS rule states we should solve the Brackets first, then the Order { x² = xx } then any Division or Multiplication, and finally any Addition or Subtraction.

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