Question

62] Save the given pair of linear equations by using elimination
दिर सार समीकरणों को विलोपन विधि द्वारा हल करें।
(2x2=4)
(
x- y = 1 ( 21+3y = 8 and 4x+
(i) 3x+4y= 10 and X-y=1​

Answer 1

3x+4y=10—————— 1
x-y=1————————- 2
Multiplying eq 1 by 4 and eq 2 by 1
3x+4y=10—————- 3
4x-4y=4—————— 4
Adding 3 and 4
3x+4x=10+4
7x=14
x=2
Substituting x=2 on eq 2
2-y=1
-y=1-2
-y=-1
y=1

Answer 2

Step-by-step explanation:

1) 3x+4y=10 __eq 1

x-y=1 __eq 2

multiplying eq 2 by 3,

3(x-y=1),

therefore, 3x-3y=3 __eq3

subtracting eq1 and eq3,

3x+4y =10

- 3x-3y =3

_______

0 + 7y = 7

therefore, y=1

substituting y=1 in eq2,

x-y = 1

therefore, x -1=1

therefore, x=1+1 = 2

check:

3x+4y = 10

3(2)+4(1)=10

6+4=10

10=10.