Question

63.2g of copper at 50°C can just melt 3.8 g ice. If the laten heat of ice is 80 then specific heat of copper

Answer 1

Answer:

Let the specific heat capacity of copper be s

∴ Heat lost by copper = 63.2 x s x (50 – 0) = 3160 s joule

Heat gained by ice = 3.8 x 336 joule.

Since Heat gained = Heat lost

We have  3160 s = 3.8 x 336 = 1276.8

Or s = (1276.8/ 3160)K/g 0C = 0.404 J/g0C

Explanation: