63.63 = m{21+(n/100)}
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8
1
m(21 + n/100) = 63.63
2100 m + mn = 6363 = 6300 + 63
m = 3 and n = 21
2
1, 5, 7, 4, 8
11, 15, 17, 14, 18
3
If N is prime then it has 2 divisors. (Prime number is having 2 divisors)
N + 1 is having 3 divisors means it is a square number (Square number is having odd number of divisors)
N = 3
divisors 1, 3
N + 1 = 4
divisors 1, 2, 4
N + 2 = 5 is prime having 2 divisors.
4
Biggest 10 digit palindrome is 9999999999
smallest 8 digit palindrome number is 11111111
find difference.
5
p/9 + q/10 = r
p/9 + p/10 = r
19p = 90r
p = 90 and r = 19
Maximum value of r = 95
when p = 450
6 p, q , (p – q), (p + q) are prime
sum = 3p + q
p and q are odd so 3p is odd
3p + q is even divisible by 2
7
a(b + c) = 32
b(c + a) = 65
c(a + b) = 32
ab + ac + bc + ab + ac + bc = 174
ab + bc + ac = 85
bc = 87 – 32 = 55
b = 11 or 5 and c = 5 or 11
ac = 85 – 65 = 20 = 5 × 4
so a = 5 or 4 and c = 4 or 5
from above conclusion a = 4, b = 11 and c = 5
abc = 220
8
Let full volume = x
0.6x = 80 + 0.2x
0.4x = 80
x = 20
10
sum of all 5 angles = 540
sum of remaining 3 angles = 540 – 180 = 360
each angle = 120°
m(21 + n/100) = 63.63
2100 m + mn = 6363 = 6300 + 63
m = 3 and n = 21
2
1, 5, 7, 4, 8
11, 15, 17, 14, 18
3
If N is prime then it has 2 divisors. (Prime number is having 2 divisors)
N + 1 is having 3 divisors means it is a square number (Square number is having odd number of divisors)
N = 3
divisors 1, 3
N + 1 = 4
divisors 1, 2, 4
N + 2 = 5 is prime having 2 divisors.
4
Biggest 10 digit palindrome is 9999999999
smallest 8 digit palindrome number is 11111111
find difference.
5
p/9 + q/10 = r
p/9 + p/10 = r
19p = 90r
p = 90 and r = 19
Maximum value of r = 95
when p = 450
6 p, q , (p – q), (p + q) are prime
sum = 3p + q
p and q are odd so 3p is odd
3p + q is even divisible by 2
7
a(b + c) = 32
b(c + a) = 65
c(a + b) = 32
ab + ac + bc + ab + ac + bc = 174
ab + bc + ac = 85
bc = 87 – 32 = 55
b = 11 or 5 and c = 5 or 11
ac = 85 – 65 = 20 = 5 × 4
so a = 5 or 4 and c = 4 or 5
from above conclusion a = 4, b = 11 and c = 5
abc = 220
8
Let full volume = x
0.6x = 80 + 0.2x
0.4x = 80
x = 20
10
sum of all 5 angles = 540
sum of remaining 3 angles = 540 – 180 = 360
each angle = 120°
ronavpuri05:
Thanks a lot!! But I only wanted (1)
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