Question

63x²+5x-2=0 solve factories method​

Answer 1

Step-by-step explanation:

• 63x^2 + 5x - 2
• 63x^2 + ( 14-9 ) x - 2
• 63x^2 +14x - 9x - 2
• 7x (9x+2) - 1 (9x+2)
• (9x+2) (7x-1)

Answer 2

Answer:

Step-by-step explanation:

Here is how to solve it

Multiply the coefficient of $x^{2}$ which is 63 and the last number which is 2.

So now we get 126.

Now factorise it,

126 = 2 x 7 x 3 x 3

So the difference between the 2 numbers whose product is 126 should be the coefficient of the 2nd term which 5.

In this case the numbers are 14 and 9

We can write 5x as 14x - 9x

So,

63$x^{2}$ + 14x - 9x - 2 = 0

Now take the HCF of 63 and 14 as well as 9 and 2.

They are 7 and 1.

Now take 7x as common in the first one and 1 as common in the second one.

So,

7x(9x + 2) -1 (9x + 2)

Now both of them have 9x + 2.

We can now write this as,

(7x - 1)(9x + 2) = 0

You can check it by opening it.

So now we can say that 7x-1 = 0  or 9x + 2=0

Now solve it. Do it yourself :)