64‐¹/³ (64‐¹/³-64²/³) find the value
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1
Answer:
64
−
3
1
×[64
3
1
−64
3
2
]
=(4
3
)
−
3
1
×[(4
3
)
3
1
−(4
3
)
3
2
]
=
4
1
.(4−4
2
)
=
4
1
.(4−16)
=−3
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