Question

(64÷125)^-2/3+1÷(256/625)^1÷4+root 25÷(64)^1/3

Answer 1

Answer:

65/16 is the Answer.

Step-by-step explanation:

Hope it will help you.

Answer 2

solution

$( \frac{64}{125} ) \frac{ -2 }{3} + 1 \div ( \frac{256}{625} ) \frac{1}{4} + \sqrt{25} \div(64) \frac{1}{4}$

$(\frac{ {4}^{3} }{ {5}^{3} } ) \frac{ - 2}{3} + 1 \div ( \frac{ {4}^{4} }{ {5}^{4} } ) { \frac{1}{4} }^{} + 5 \div ({4 {}^{3} }^{} ) \frac{1}{3}$

$( \frac{4}{5} ) {}^{ - 2} + 1 \div ( \frac{4}{5} ) + 5 \div 4$

$(\frac{5}{4} ) {}^{2} + 1 \times \frac{5}{4} + \frac{5}{4}$

$\frac{25}{16} + \frac{5}{4} + \frac{5}{4}$

take LCM

$(25 + 20 + 20) \div 16$

$\frac{65}{16}$

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