Question

(64/125)∧-2/3 +(625/256)∧1/4 +√253/ 3√64

Answer 1

my b p
ll. I'm l.ll me m lll mm be. dd, Nicole,, l

Answer 2

Hey friend,
Here is the answer you were looking for:
${( \frac{64}{125} )}^{ - \frac{2}{3} } + {( \frac{625}{256} )}^{ \frac{1}{4} } + \frac{ \sqrt{253} }{3 \sqrt{64} }$

We can also write it as :

$= {( \frac{4}{5} )}^{ 3 \times - \frac{2}{3} } + {( \frac{5}{4} )}^{4 \times \frac{1}{4} } + \frac{ \sqrt{253} }{3 \sqrt{8 \times 8} } \\ \\ = {( \frac{4}{5} )}^{ - 2} + {( \frac{5}{4} )}^{1} + \frac{ \sqrt{253} }{3 \times 8} \\ \\ = {( \frac{5}{4} )}^{2} + \frac{5}{4} + \frac{ \sqrt{253} }{24} \\ \\ = \frac{25}{16} + \frac{5}{4} + \frac{ \sqrt{253} }{24} \\ \\ = \frac{25 \times 3 + 5 \times 12 + \sqrt{253} \times 2}{48} \\ \\ = \frac{75 + 60 + 2 \sqrt{253} }{48} \\ \\ = \frac{135 + 2 \sqrt{253} }{48}$

Hope this helps!!

If you have any doubt regarding to my answer, feel free to ask in the comment section or inbox me if needed.

@Mahak24

Thanks...
☺☺