Math, asked by darshryan, 1 year ago

[(64)^(2/3)]-[( 5)]-[(2)^(5])+[(27)^(-2/3])*[(25/9)^(-1/2)]

Answers

Answered by PrincessStargirl
13

Heya!


Here is your answer.


Answer: -20.933


Step-by-step solution:


[(64)^(2/3)]-[( 5)]-[(2)^(5])+[(27)^(-2/3])*[(25/9)^(-1/2)]


= 64^2/3-5-2^5+(27^-2/3) ((25/9)^-1/2)


= 16-5-2^5+(27^-2/3)((25/9)^-1/2


= 11-2^5+(27^-2/3)((25/9)^-1/2


= 11-32+(27^-2/3)((25/9)^-1/2


= -21+(27^-2/3)((25/9)^1/2)


= -21+0.111111(29/9)^1/2


= -21+(0.111111)(0.6)


= -21+0.066667


,= -20.933



⭐Hope it helps⭐

Answered by ans81
1
HEY MATE HERE IS YOUR ANSWER

 <b>

 = > (64 {)}^{ \frac{2}{3} } - (5) - (2 {)}^{5} + (27 {)}^{ \frac{ - 2}{3} } \times ( \frac{25}{9} {)}^{ \frac{ - 1}{2} }


➡️ 31 answer

Hope it will help you

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