Math, asked by alplali48, 1 year ago

Find 777777777.......99times and99999999999... 77times

Answers

Answered by harshavardhan2125
0
76,999,999,923


7,699,999,999,923

done.

alplali48: How
Answered by Akhileshsah
1
we have A=999...9
A=999...9 which has 7777digits and B=777..7
B=777..7 which has 9999digits.

Now Let X=777..7X=777..7 which has 7777 digits and Y=777..7000...0Y=777..7000...0 which has 2222sevens and 7777 Zeros. So

B=777..7+777..7000...0=X+YB=777..7+777..7000...0=X+Y

Also Y=Z∗1077Y=Z∗1077 where Z=777..77Z=777..77with 2222 Sevens.

AB=A(X+Y)AB=A(X+Y)

According to your Note

AX=777..76222...23AX=777..76222...23

which has 7676 Sevens and 7676 Twos.So Total digits of number AXAX is 154154.

Similarly

AY=0000..0777..7000..0AY=0000..0777..7000..0

which has 5555 Zeros in front, 2222 Sevens and 7777 Zeros at last with total digits as again 154154. Now simply add AXAX and AYAYby aligning 154154 digits of AXAX with corresponding 154154 digits of AYAY you will get the answer.
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