Math, asked by atty6445, 11 months ago

√64=4^n, what is the value of n

Answers

Answered by Anonymous
3

Answer:

\large\boxed{\sf{n=\dfrac{3}{2}}}

Step-by-step explanation:

From the given question, we have

 \sqrt{64}    =  {4}^{n}

Further solving, we get

 =  >  \sqrt{ {8}^{2} }  =  {4}^{n}  \\  \\  =  >  { ({8}^{2}) }^{ \frac{1}{2} }  =  {4}^{n}  \\  \\  =  >  {8}^{(2 \times  \frac{1}{2}) }  =  {4}^{n}  \\  \\  =  >  {8}^{1}  =  {4}^{n}  \\  \\  =  >  {4}^{n}  = 8 \\  \\  =  >  {( {2}^{2} )}^{n}  =  {2}^{3}  \\  \\  =  >  {2}^{2n}  =  {2}^{3}

Now, bases are same, therefore, exponent must be same.

Therefore, we will get,

 =  > 2n = 3 \\  \\  =  > \bold{ n =  \dfrac{3}{2}}

Concept Map :-

  •  {x}^{m}  \times  {x}^{n}  =  {x}^{(m + n)}

  •  \sqrt{ {x}^{2} }  = x

  •  \sqrt[m]{x}  =  {x}^{ \frac{1}{m} }

  •  { ({x}^{m}) }^{n}  =  {x}^{mn}
Answered by madhutiwari793
4

n=3/2

√64=√4^3

sq root is equal to power raised to 1/2

so √64=(4^3)to the powers1/2

 {4 {}^{3} }^{1 \div 2}

so √64=. { ( a^m)^n= a^mn}

 {4}^{3 \div 2}

so n=3/2

please mark BRAINIEST

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