Question

64. A compound AB with molecular mass 60 g molis
dissolved in a solvent having density 0.26 g mL-1
Assuming no change in volume upon dissolution,
the molality of 3.9 molar solution is​

Answer 1

Answer:

In 3.2 molar solution,

We have amount of solute = 3.2 mol

Volume of solution = 1.0 L

Since there occurs no change in volume on dissolving solute,

Volume of solvent = 1L

Mass of solvent = (1.0L)(0.4 gmL-1)

                             = (103mL)(0.4 gmL-1)

                              =400 g =0.4kg

Molality of the solution = 3.2/0.4 =8molkg-1