Math, asked by vempatapuvasantha, 7 months ago

find the value of (4n-1)^2​

Answers

Answered by sshailshetty
0

Answer:

-1 / 2

Step-by-step explanation:

4n+2 = 0

4n = 0 - 2

4n = -2

n = -2 / 4

n = -1 / 2

hope it helps .

Answered by Nischalunstoppable
2

(4n-1)²

(a-b)²= a²-2ab+b²

(4n-1)²= (4n)²-2(4n)(1)+(1)

= 16n²-8n+1

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