Question

64 identical drops each charged to 0.9 volt, combine and form a single large spherical drop. The potential of this

Answer 1

Let potential of each small drop = Kq/r = V (in your case, 10 V).

We know, Volume of n (here 27 small drops) drops = Volume of one big drop.

which implies:

n * 4/3 pi r³ = 4/3 pi R³

where, r is radius of small drop and R is the radius of big drop.

Therefore , R = n⅓ * r and also charge remains conserved.

Therefore, charge on 1 small drop = q and charge on big drop containing n drops = nq .

Therefore,

potential on big drop = K (nq)/ (n⅓)r

= (n⅔) Kq/r

= (n⅔) V

Now substitute the n with the number of drops you wish to combine and do the math.

—

Potential of each small drop = 10V.

No. of drpos : 27.

Potential on big drop = 10*K(27q)/(27⅓)r.

=(10 * 27)/3 Kq/r

=(10 * 27)/3 V

= 90V

Answer 2

Answer:

Explanation: Full explanation is given in answer