Question

64(x²+y²) -16(x²+y²)

Answer 1

16(x²+y²) [4 - 1]
16(x²+y²)[3]
48(x²+y²)
You can do it using easier methods too

Answer 2

$64( {x}^{2} + {y}^{2} ) - 16( {x}^{2} + {y}^{2} )$
by taking out the common factors,we have
$( {x}^{2} + {y}^{2} )(64 - 16)$
$= ( {x}^{2} + {y}^{2} )(48)$
is the answer