64a^2-64a+16. help please please please please please please please please please
Answers
Answer:
Step-by-step explanation:
(pull out like factors)
64a2 - 64a + 16 = 16 • (4a2 - 4a + 1)
Factoring 4a2 - 4a + 1
The first term is, 4a2 its coefficient is 4 .
The middle term is, -4a its coefficient is -4 .
The last term, "the constant", is +1
Step-1 : Multiply the coefficient of the first term by the constant 4 • 1 = 4
Step-2 : Find two factors of 4 whose sum equals the coefficient of the middle term, which is -4 .
-4 + -1 = -5
-2 + -2 = -4 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -2 and -2
4a2 - 2a - 2a - 1
Step-4 : Add up the first 2 terms, pulling out like factors :
2a • (2a-1)
Add up the last 2 terms, pulling out common factors :
1 • (2a-1)
Step-5 : Add up the four terms of step 4 :
(2a-1) • (2a-1)
Which is the desired factorization
Multiplying Exponential Expressions:
3.3 Multiply (2a-1) by (2a-1)
The rule says : To multiply exponential expressions which have the same base, add up their exponents.
In our case, the common base is (2a-1) and the exponents are :
1 , as (2a-1) is the same number as (2a-1)1
and 1 , as (2a-1) is the same number as (2a-1)1
The product is therefore, (2a-1)(1+1) = (2a-1)2
Final result :
16 • (2a - 1)2
Answer:
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