Question

64a^2-64a+16. help please please please please please please please please please​

Answer 1

Answer:

Step-by-step explanation:

(pull out like factors)

64a2 - 64a + 16  =   16 • (4a2 - 4a + 1)

Factoring  4a2 - 4a + 1

The first term is,  4a2  its coefficient is  4 .

The middle term is,  -4a  its coefficient is  -4 .

The last term, "the constant", is  +1  

Step-1 : Multiply the coefficient of the first term by the constant   4 • 1 = 4  

Step-2 : Find two factors of  4  whose sum equals the coefficient of the middle term, which is   -4 .

     -4    +    -1    =    -5  

     -2    +    -2    =    -4    That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above,  -2  and  -2  

                    4a2 - 2a - 2a - 1

Step-4 : Add up the first 2 terms, pulling out like factors :

                   2a • (2a-1)

             Add up the last 2 terms, pulling out common factors :

                    1 • (2a-1)

Step-5 : Add up the four terms of step 4 :

                   (2a-1)  •  (2a-1)

            Which is the desired factorization

Multiplying Exponential Expressions:

3.3    Multiply  (2a-1)  by  (2a-1)  

The rule says : To multiply exponential expressions which have the same base, add up their exponents.

In our case, the common base is  (2a-1)  and the exponents are :

         1 , as  (2a-1)  is the same number as  (2a-1)1  

and   1 , as  (2a-1)  is the same number as  (2a-1)1  

The product is therefore,  (2a-1)(1+1) = (2a-1)2  

Final result :

 16 • (2a - 1)2

Answer 2

Answer:

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