64a^3+b^3+48a^2b+12ab^2
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Answer:
(((64•(a3))+((48•(a2))•b))+(22•3ab2
(((64•(a3))+((24•3a2)•b))+(22•3ab2)
((26a3 + (24•3a2b)) + (22•3ab2))
4.1 Factoring: 64a3+48a2b+12ab2+b3
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64a3+48a2b+12ab2+b3 is a perfect cube which means it is the cube of another polynomial
In our case, the cubic root of 64a3+48a2b+12ab2+b3 is 4a+b
Factorization is (4a+b)3
Final result :
(4a + b)3
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