Math, asked by sushantha6963, 7 months ago

[64a^6 b^-12] ^1/6
Please can son one help me solve this

Answers

Answered by davesuquo
1

Answer:

((64*a^6*b^12)^1)/6 = 0

(64*a^6*b^12)/6 = 0

32/3*a^6*b^12 = 0

Step-by-step explanation:

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