64m cube-343n cube factorise
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Answered by
89
64m^3-343n^3
(4m)^3- (7n)^3
a^3-b^3=(a-b) (a^2+ab+b^2)
(4m-3n) [ (4m)^2+4m*3n+(3n)^2]
(4m-3n) ( 16m^2+12mn+9n^2)
(4m)^3- (7n)^3
a^3-b^3=(a-b) (a^2+ab+b^2)
(4m-3n) [ (4m)^2+4m*3n+(3n)^2]
(4m-3n) ( 16m^2+12mn+9n^2)
Answered by
17
the answer is given below
(4m-3n)(16m^2+12mn+9n^2)
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