64x³ +1
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64x^3 + 1
》( 4x )^3 + ( 1 )^3
According to the identity ,
( a + b )^3 = ( a + b )( a^2 + ab + b^2 )
》( 4x + 1 )[ ( 4x )^2 - ( 4x )( 1 ) + ( 1 )^2 ]
》( 4x + 1 )( 16x^2 - 4x + 1 )
Thank you .
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