Question

the numbers (3x - 1), (2x + 5) and (4x + 2) are in AP, then value of x.​

Answer 1

Step-by-step explanation:

correct option is C 5

2x,x+8,3x+1 are in A.P.

Thus,

(x+8)−2x=(3x+1)−(x+8)

8−x=2x−7

3x=15

x=5

Answer 2

Answer:

The value of x = 3

Step-by-step explanation:

Given,

The numbers  (3x - 1), (2x + 5) and (4x + 2) are in AP

To find,

The value of 'x'

Recall the concept

If three numbers a,b, and c are in AP, then we have b-a = c-b = d, where 'd' is called the common difference of the AP

Solution:

Since the numbers (3x - 1), (2x + 5) and (4x + 2) are in AP we have

(2x + 5) - (3x-1) = (4x+2)-(2x+5)

2x+5 -3x+1 = 4x +2 -2x -5

-x+6 = 2x -3

3x = 9

x = 3

∴The value of x = 3

Answer:

The value of x = 3

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