Question

(64y^2-4) divide by (4y-1)

Answer 1

Answer:

2(8y+2) or 16y+4 or 4(4y+1)

Step-by-step explanation:

see (a-b)^2 = (a+b)(a-b)

hence 64$y^{2}$ - 4 = (8y+2)(8y-2) =(8y+2) * 2*(4y-1) then we just divide by

(4y-1) so

(4y-1)  will get cancelled hence what remains is that 2(8y+2).

Thank you.