Question

66 = 3xsquare - 12x +x -4​

Answer 1

Step-by-step explanation:

66=3x^2-12x+x-4

66=3x^2-11x-4

66= 3x^2-11x-4

66+4= 3x^2-11x

70= 3x^2-11x

/70

Answer 2

Answer:

Step-by-step explanation:

We have

      3x^2 - 12x + x - 4 = 66

     3x^2 - 11x - 4 - 66 = 0

      3x^2 - 11x - 70 = 0

      3x^2 - 21x +  10x - 70 = 0

      3x ( x - 7 ) + 10 ( x - 7 ) = 0

      (3x + 10 )(x - 7) = 0

so there will be two values of x = -3/10 and 7

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