66) If a, 5 m/s2 & 0-45° then la is found to be:
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D
40:1
Horizontal velocity, vx=20cos(45o)=102m/s
Vertical Velocity , vy=20sin(45o)=102m/s
Using s=ut+21at2 h=102t−21×10×t2 ....1
⇒x=102t ⇒t=102x
Put the value of t in equation 1, we get
h=x−401x2,
By comparing the given equation of trajectory, ⇒A=1 and B=401
Hence, A:B=1:401=40:1
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