Physics, asked by yashgarg195, 9 months ago

66. What is the current in the circuit shown (Fig.) ?
(1) 1.5 A
(3) 2.5 A
(2) 0.5 A
(4) None of these​

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Answered by sanjaysuthar1895
2

solution: as shown in figure there are three are connected where first two are connected in series and third is parallel w. r. t. first two

the equivalent resistance(R) of there resister is 4/3 ohm

according to ohm's law V=IR

I=V/R

putting the values

I=2×3/4= 1.5A

Answered by tarakaramachowdaryma
0

Answer:

1.5A

R=2×2×2/2+2+2=8/6=4/3

V=IR

i=V/R

i=2x3/4=1.5A

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