Question

66(y^4-5y^3-24y^2)÷6y(y-8)



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Answer 1

Answer:

Graph for 66*(y^4-5*y^3-24*y^2)/(6*y)*(y-8)

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Answer 2

Answer:

$\frac{66(y^4-5y^3-24y^2)}{6y(y-8)}$ = 11y(y+3)

Step-by-step explanation:

Given expression is

$\frac{66(y^4-5y^3-24y^2)}{6y(y-8)}$

Required to simplify the given expression

Solution

We have, the  expression

Taking the common factor 'y²' in the numerator we get,

$\frac{66y^2(y^2-5y-24)}{6y(y-8)}$

Cancelling the common term 6y from the numerator and denominator we get

$\frac{66y^2(y^2-5y-24)}{6y(y-8)}$= $\frac{11y(y^2-5y-24)}{(y-8)}$

factorize the quadratic polynomial y²-5y-24 we get

y²-5y-24 = y²-8y+3y-24

=y(y-8)+3(y-8)

=(y+3)(y-8)

y²-5y-24 = (y+3)(y-8)

Substituting in the equation we get,

  $\frac{11y(y^2-5y-24)}{(y-8)}$ = $\frac{11y(y+3)(y-8)}{(y-8)}$

cancel the common term (y-8) we get

=11y(y+3)

∴ $\frac{66(y^4-5y^3-24y^2)}{6y(y-8)}$ = 11y(y+3)

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