Math, asked by rroy39065, 1 month ago

67. What is the equation of the line which passes
through (4,-5) and is perpendicular to
3x + 4y + 5 = 0?
2013 II
(a) 4x - 3y - 31 = 0
(b) 3x – 4y - 41 = 0
(c) 4x + 3y - 1 = 0
(d) 3x + 4y + 8 = 0

Answers

Answered by ankushsaini23

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Correct answer is

(a) 4x - 3y -31 = 0

Answered by ᎷᎪᎠᎪᎡᎪ

What is the equation of the line which passes

What is the equation of the line which passesthrough (4,-5) and is perpendicular to

What is the equation of the line which passesthrough (4,-5) and is perpendicular to3x + 4y + 5 = 0?

What is the equation of the line which passesthrough (4,-5) and is perpendicular to3x + 4y + 5 = 0?2013 II

(b) 3x – 4y - 41 = 0

(b) 3x – 4y - 41 = 0(c) 4x + 3y - 1 = 0

(b) 3x – 4y - 41 = 0(c) 4x + 3y - 1 = 0(d) 3x + 4y + 8 = 0

(a) is correct

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