672 ml of ozonised oxygen gass is weigh 1gm .calculate the volume of ozobe at sample
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in this question you can use the ideal gas equation (pressure * volume= no of moles* universal gas constant * temperature)
start using the unitary method and the mole fraction of the gaseous mixture to get the answer
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start using the unitary method and the mole fraction of the gaseous mixture to get the answer
2 years ago
Think You Can Provide ABetter Answer ?
Answer & Earn Cool Goodies
Other Related Questions on Physical Chemistry
5 mole of an ideal gas expands reversible from a volume of 8dm³ to 80dm³ at a temp 27c the change in...Answer & Earn Cool Goodies
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Answered by
0
Explanation:
Let, the volume of O
3
=x mL.
Volume of O
2
present =(600−x) mL
22400 mL of O
3
and O
2
at STP will weight 48 g and 32 g respectively.
The weight of x mL of O
3
=
22400
x×48
g.
The weight of (600−x) mL of O
2
=
22400
(600−x)
×32.
Total weight of ozonised O
2
(600mL) =
22400
48x
+
22400
(600−x)×32
=1.0.
∴x=200 mL
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