Question

68
Three machines P. Py, and Py in a certain factory produce 50%, 0% and 25%, respectively, of the total daily output of de thes. It is the
the tubes produced by each of the machines P, and P, are defective and that 4% of those produced on P, are defective. If one tube sich
side wa
from a day's production, calculate the probability that the defective tube was produced on machine P1
A. 97
70836-1
3. O 8/7
O 6/7
0 5/7​

Answer 1

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

of electric tubes. It is known that 4 % of the tube produced on each of machines E1 . and ...

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Three Machines E1, E2, E3 in a Certain Factory Produce 50%, 25 ...

Advertisement Remove all ads ... If one tube is picked up at random from a day's production, then calculate the ... Let A be the event that the tube picked is defective. ... P ( A | E 1 ) = 4

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EX 31.6 Q13 Three machines E1,E2,E3 in a certain factory ...

1 answer

Three machi

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