Math, asked by shekarmashetty72, 2 months ago

68
Three machines P. Py, and Py in a certain factory produce 50%, 0% and 25%, respectively, of the total daily output of de thes. It is the
the tubes produced by each of the machines P, and P, are defective and that 4% of those produced on P, are defective. If one tube sich
side wa
from a day's production, calculate the probability that the defective tube was produced on machine P1
A. 97
70836-1
3. O 8/7
O 6/7
0 5/7

Answers

Answered by suresh2017tax

Step-by-step explanation:

CIA's ft o FFS DC hmm loop of CT DHL if DC k

Answered by kumarupdesh1982

Step-by-step explanation:

of electric tubes. It is known that 4 % of the tube produced on each of machines E1 . and ...

Imagehttps://www.shaalaa.com › three-ma...

Three Machines E1, E2, E3 in a Certain Factory Produce 50%, 25 ...

Advertisement Remove all ads ... If one tube is picked up at random from a day's production, then calculate the ... Let A be the event that the tube picked is defective. ... P ( A | E 1 ) = 4

Imagehttps://goprep.co › ex-31.6-q13...

EX 31.6 Q13 Three machines E1,E2,E3 in a certain factory ...

1 answer

Three machi